c^2-8c+16=4

Solution for c^2-8c+16=4 equation:

Simplifying
c2 + -8c + 16 = 4

Reorder the terms:
16 + -8c + c2 = 4

Solving
16 + -8c + c2 = 4

Solving for variable 'c'.

Reorder the terms:
16 + -4 + -8c + c2 = 4 + -4

Combine like terms: 16 + -4 = 12
12 + -8c + c2 = 4 + -4

Combine like terms: 4 + -4 = 0
12 + -8c + c2 = 0

Factor a trinomial.
(2 + -1c)(6 + -1c) = 0

Subproblem 1
Set the factor '(2 + -1c)' equal to zero and attempt to solve:

Simplifying
2 + -1c = 0

Solving
2 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -1c = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -1c = 0 + -2
-1c = 0 + -2

Combine like terms: 0 + -2 = -2
-1c = -2

Divide each side by '-1'.
c = 2

Simplifying
c = 2
Subproblem 2
Set the factor '(6 + -1c)' equal to zero and attempt to solve:

Simplifying
6 + -1c = 0

Solving
6 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + -1c = 0 + -6

Combine like terms: 6 + -6 = 0
0 + -1c = 0 + -6
-1c = 0 + -6

Combine like terms: 0 + -6 = -6
-1c = -6

Divide each side by '-1'.
c = 6

Simplifying
c = 6
Solution
c = {2, 6}